lab report

The police of conversation of heat energy Objective: To aggregated calefactive and dusty liquid together and predict the temperature of the pastiche. Equipment/Materials: Styrofoam transfuse, peck scale, Procedures: 1.Take a dry Styrofoam instill mass the cupful and record. 2.Pour more or less 50 mL to 60 mL mothy luxuriate in the cup. commode the cup + frosty H2 O. Record. 3.Take the temperature of dusty H2 O and record. 4.Take about 90 mL to 100 mL of sulfurous water. 5.Record the temperature of hot H2 O. 6.Mix the hot water with cold water. Stir lightly and take the temp of the concoction. 7.Record the mass of the cup + cold H2 O+ hot H2 O. 8.Clean up work area. information: pot of Styrofoam = 3.9g Temperature of cold water = 21̊C kettle of fish of Styrofoam cup + cold water = 52.9g Temperature of hot water = 72̊C chain reactor of Styrofoam cup + cold water + hot water = 142.1g Temperature of the mixture = 51̊C Calculations: 1.Calculate the mass of cold water. Mass of cup + cold water mass of Styrofoam 52.9g 3.9g = 3.0g 2.Calculate the mass of hot water. Mass of Styrofoam cup + cold water + hot water - Mass of cup + cold water 142.1g 52.9.9g = 89.2g 3.Calculate the temperature of the mixture by applying the law of converstion of heat and energy: (m ∆T Cp)cold water =(m ∆T Cp)hot water (49.0g)(x-21)̊C (4.184 J/g ̊C) = 89.2g (72-x)̊C (4.184 J/g ̊C) 49.0x 1029 = -89.2x + 6422.4 +89.2x +89.2x 138.

2x 1029 = 0 + 6422.4 + 1029 +1! 029__ 0 7451.4 138.2x= 7451.4 138.2 138.2 X=53.9̊C 4. Find the % error. (Real #) - ( your #) x 100 = % error (Real #) (53.9̊C) - (51̊C) x 100 = 5.3% (53.9̊C) Conclusion: The percentage error in this experiment was 5.3%. The reasons for experimental errors are: warmth disadvantage to the surroundings. ...If you want to get a full essay, rear it on our website: BestEssayCheap.com

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